The number of solutions for each system of two linear equations.
Zero
Solutions
One
Solution
Infinitely
Many
Solutions
2x + 2y = 3
4x + 4y = 6
7x + 5y = 8
7x + 2y = 8
-2x + 3y = 7
2x - 3y = -7

system (1) ⇒ Infinitely Many Solutions

system (2) ⇒ One Solution ⇒ ( 8/7 , 0)

system (3) ⇒ Infinitely Many Solutions

Step-by-step explanation:

A) The first system of two linear equations.

2x + 2y = 3 ⇒(1)

4x + 4y = 6 ⇒(2)

If we multiply equation (1) by 2, we will get equation (2)

So, the system in fact represents one equation.

So, The system has Infinitely Many Solutions

B) The second system of two linear equations.

7x + 5y = 8 ⇒(1)

7x + 2y = 8 ⇒(2)

By subtract (1) - (2) we will get:

5y - 2y = 0

3y = 0

y = 0

Substitute at (1)

7x + 0 = 8

x=8/7

So, The system has only One Solution ⇒( 8/7 , 0)

C) The last system of two linear equations.

-2x + 3y = 7

2x - 3y = -7

If we multiply equation (1) by -1, we will get equation (2)

So, the system in fact represents one equation.

So, The system has Infinitely Many Solutions

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

its d. the first coordintaes are 10,32

step-by-step explanation: