An isosceles triangle has a base 10 units long. If the congruent side lengths have measures to the first decimal place, what is the shortest possible length of the sides?

5.1 units

Step-by-step explanation:

At first we should know that, the sum of the lengths of any two sides of a triangle is greater than the length of the remaining side.

Given: An isosceles triangle has a base 10 units long.

Let the length of each side of the congruent sides = x

So, x + x > 10

2x > 10

x > 5

the congruent side lengths have measures to the first decimal place,

So, the congruent side lengths have measures to the nearest tenths.

So, the shortest possible length of the sides = 5.1 units

could you provide figure.