A linear function passes through the point (1,5)and (7,23)what are the rate of change and initial value?

The rate of change = 3

Initial value = 2

Step-by-step explanation:

The linear function has the form ⇒ y = mx + c

Where m is the slope or the rate of change, and c is y-intercept.

Given: A linear function passes through the point (1,5)and (7,23)

So, m = (y₂-y₁)/(x₂-x₁) = (23-5)/(7-1) = 18/6 = 3

So, y = 3x + c

By substitution with the point (1,5)

So, at x = 1 , y = 5

5 = 3*1 + c

c = 5 - 3 = 2

∴ y = 3x + 2

so, the rate of change = 3

And initial value = 2

initial value is the value at which x = 0 which is the y-intercept

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12