Triangle ABC has perimeter 22cm.
AB = 8cm
BC = 5cm
By calculation, deduce whether triangle ABC is a right-angled triangle.

ΔABC is not a right angled triangle.

Step-by-step explanation:

Perimeter = AB + BC + AC

⇒ AC = 22 - (8 + 5) = 22 - 13 = 9 cm

AC² = AB² + BC²

⇒ AC² = 9² = 81

⇒ AB² + BC² = 8² + 5² = 64 + 25 = 89

∴ AC² ≠ AB² + BC²

⇒ ΔABC is not a right angled triangle.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

351°f

step-by-step explanation: