Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that . If a beam can hold 2,000 pounds at 15 feet, what maximum length should be used to safely support 500 pounds? 6 feet 60 feet 150 feet

60feets

Step-by-step explanation:

The question is incomplete. The complete question is "Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that y = k/x. If a beam can hold 2,000 pounds at 15 feet, what maximum length should be used to safely support 500 pounds"

Since y = k/x

k = xy

If a beam can hold 2,000 pounds at 15 feet, x = 15ft y = 2000pounds

K = 15×2000

k = 30,000

To get the maximum length that should be used to safely support 500 pounds, we will use the relationship k = xy where y = 500pounds, k = 30000

x = k/y

x = 30000/500

x = 60feets

The maximum length that should be used to safely support 500 pounds is 60feets

step-by-step explanation:

this woman was an important writer and propagandist during the american revolution. she was a member of the committee of correspondence (in fact the committee was formed in her home) and was an advisor to many of the revolutionary leaders, including george washington and john adams. who was this revolutionary woman?