Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was well above the class average. The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67, what is the raw score for his exam grade?

The raw score for his exam grade is 99.69.

Step-by-step explanation:

Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.

To find : What is the raw score for his exam grade?

Solution :

The formula use to find the z-score is

Where, z=1.67 is the z-score

 is the means

is the standard deviation

x  is the raw score for his exam grade

Substitute the values,

Therefore, the raw score for his exam grade is 99.69.

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2