33.2 This exercise could have appeared just as easily in §4. Let S be a nonempty bounded subset of R. For fixed c > 0, let cS = {cs : s ∈ S}. Show sup(cS) = c · sup(S) and inf(cS) = c · inf(S).

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

i'm a sophomore in connections, i'd recommend checking on jishka.com they have a large range of questions and answers from our school.