At a particular restaurant, each slider has 225 calories and each chicken wing has 70 calories. A combination meal with sliders and chicken wings has a total of 7 sliders and chicken wings altogether and contains 1110 calories. Write a system of equations that could be used to determine the number of sliders in the combination meal and the number of chicken wings in the combination meal. Define the variables that you use to write the system. PLEASE I NEED THIS ANSWER

The equations that can be used to solve the question will be x + y = 7; 225x + 70y = 110.

Therefore, based on the information given, the first equation will be:

x + y = 7

On the other hand, the second equation will be:

225(x) + 70(y) = 110

225x + 70y = 110

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The appropriate equation for the above mentioned conditon would be

x+y=7

225x+70y=1110

Step-by-step explanation:

As mentioned in the question the meals contain just two delicacies (i.e. sliders and chicken wings)

Let the number of Sliders be represented by “x”

Let Number of Chicken wings be represented as “y”

As given in the question the total number of sliders and chicken wings equals 7

Hence  x + y =7… Equation 1  

Further, it is mentioned that each slider carries worth 225 calories of energy and chicken wing carries 70 calories of energy. Total calorie of a meal which contains sliders and wings is 1110 calories.

Thus, Total energy carried by sliders individually = total sliders* energy carried by one slider= 225x

Similarly, Total energy carried by wings individually = total chicken wings* energy carried by one wing= 70y

Thus 225x+70y=1110...  Equation 2

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.