A rectangle has a height of 7 and a width of 2x^2-3

Don't know what you want to know but the area and perimeter is drown below

Step-by-step explanation:

Area = 7(2x^2 - 3)

periminter = 7 + 7 + (2x^2-3) + (2x^2-3)

= 14 + 4x^2 - 6

= 4x^2 + 8

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.