Each time a shopper purchases a tube of toothpaste, he chooses either brand A or brand B. Suppose that for each purchase after the first, the probability is 1/3 that he will choose the same brand that he chose on his preceding purchase and the probability is 2/3 that he will switch brands. If he is equally likely to choose either brand A or brand B on his first purchase, what is the probability that both his first and second purchases will be brand A and both his third and fourth purchases will be brand B

Step-by-step explanation:

Let the required probability be denoted by P(1A 2A 3B 4B).

This means a shopper chooses brand A first. Then by choosing brand A as the second purchase, the same brand is used. The third purchase is brand B; hence he switches brand. The fourth purchase is also brand B, maintaining the same brand as the third.

On the first purchase, the probabilities of A and B are both equal. Hence, each probability = 1/2

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

it is true

step-by-step explanation:

all the combinations add up i used   calculator