Each of 16 store cashiers worked an average of 21 hours per week and is paid 8.25 per hour. After the store manager hires 2 additional cashiers, each cashier will be paid 0.25 more per hour and will work an average of 1.5 hours per week.

$211.50

Step-by-step explanation:

Complete Question:

Each of 16 store cashiers worked an average of 21 hours per week and is paid 8.25 per hour. After the store manager hires 2 additional cashiers, each cashier will be paid 0.25 more per hour and will work an average of  1.5 fewer hours per week. What will be the change in the total amount of money the cashiers are paid each week?

Solution:

Total Sum Hours = 21 * 16 = 336 hours

At $8.25 per hour, the cost is:

8.25*336 = $2772

Now,

2 more cashier means: 16 + 2 = 18 cashiers

New rate is 0.25 dollars more, so new rate is:

8.25 + 0.25 = $8.50 per hour

Average 1.5 hrs less is an average of 21 - 1.5 = 19.5 hours

Now,

Total Sum hours = 18 * 19.5 = 351 hours

At $8.50 per hour, the cost is:

8.50 * 351 = $2983.50

Total change in money paid to cashiers in a week would be:

2983.50 - 2772 = $211.50

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

"exterior angles = 360 / number of sides.

60 = 360 / sides

sides = 360 / 60

sides = 6"