Mathematics, 12.03.2020 21:32 lilly4920
Given the equation y ln (x^2 + y^2 + 8) = 3, evaluate dy/dx. Assume that the equation implicitly defines y as a differentiable function of x.
Answers: 1
:![\dfrac{\mathrm dy}{\mathrm dx}\ln(x^2+y^2+8)+y\dfrac{\frac{\mathrm d}{\mathrm dx}[x^2+y^2+8]}{x^2+y^2+8}=0](/tpl/images/0545/4768/f0fcc.png)
![\dfrac{\mathrm d}{\mathrm dx}[x^2+y^2+8]=2x+2y\dfrac{\mathrm dy}{\mathrm dx}](/tpl/images/0545/4768/a4b8c.png)
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Given the equation y ln (x^2 + y^2 + 8) = 3, evaluate dy/dx. Assume that the equation implicitly def...
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