![\sqrt{16x^2-37x-2} =4x-5\\squaring~ both~sides\\16x^2-37x-2=16x^2-40x+25 ~[(a-b)^2=a^2-2ab+b^2]\\16x^2-37x-2-16x^2+40x-25=0\\3x-27=0\\3(x-9)=0\\x-9=0\\x=9](/tpl/images/0545/3558/46825.png)
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solve for me plz with explanation...
Mathematics, 12.03.2020 20:28 naeaamm2528
5+
solve for me plz with explanation
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