Solve the following systems by substitution

question 1
x=5
2x+y=10

question 2
x++16y=20
x=4y

question 3
2x+8y=20
x=2

The answer to your question is below

Step-by-step explanation:

Question 1

                x = 5                       Equation l

                2x + y = 10              Equation ll

- Substitute Equation l in equation ll

               2(5) + y = 10

                y = 10 - 10

                y = 0

- Solution  (5, 0)

Question 2

                 x + 16y = 20          Equation l

                 x = 4y                    Equation ll

Substitute equation ll in equation l

                4y + 16y = 20

                        20y = 20

                           y = 20/20

                           y = 1

-Find x

                x = 4(1)

                x = 4

-Solution

                (4, 1)

Question 3

                   2x + 8y = 20            Equation l

                     x = 2                       Equation ll

-Substitute equation ll in equation l

                   2(2) + 8y = 20

                      4 + 8y = 20

                            8y = 20 - 4

                            8y = 16

                              y = 16/8

                              y = 2

- Solution

                   (2, 2)              

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the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870