A circle with center c(4,-2) contains the point D(8,1). what is the equation of the line perpendicular to the radius of the circle passing through point c?

Step-by-step explanation:

slope of CD=(1+2)/(8-4)=3/4

slope of line ⊥ to CD=-4/3

eq. of line with slope -4/3 and passing through (4,-2) is

y-y1=m(x-x1)

y+2=-4/3(x-4)

3y+6=-4x+16

3y=-4x+16-6

3y=-4x+10

or 4x+3y-10=0

this is the eq. of line in the form  ax+by+c=0

or in slope form

y=-4/3 x- 10/3

it is probably the graph on the bottom right.

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.