Farmer John has 51 hens. If he had three more solid colored hens, then exactly one-third of his hens would be speckled. From years of experience, Farmer John knows that one-half of the speckled hens will lay speckled eggs and that each hen and a half will lay an egg and a half in a day and a half. After how many full days will Farmer John have 15 dozen speckled eggs to sell?

Step-by-step explanation:

Total number of hens John has  = 51 hens

If there are 3 more hens, then total number of hens  = 51 + 3  = 54 hens

Now, one third of the hens are speckled.

⇒ 18 hens are speckled.

Now, of the  total 18 speckled hens  lay speckled eggs.

⇒ 9 hens produce speckled eggs.

Now, one hen lays one egg in a day and a half.

⇒  9  hens lay nine eggs in a day and a half .

⇒  9 hens lay  180 (15 doz.) eggs in days

Hence,  after full 30 days John will have 15 dozen speckled eggs to sell.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

answer: apothems is your answer

step-by-step explanation: hope u get it right