The weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that can be set by the operator. At what level should the mean weight be set if it required that only 1% of the bags weigh less than 10.5 kilograms? Round the answer to 2 decimal places.

Step-by-step explanation:

Given that the  weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that can be set by the operator.

Let the mean be M.

Only 1% of the bags weigh less than 10.5 kilograms

i.e. P(X<10.5) = 0.01

corresponding Z value for P(Z<z) = 0.01 is -0.025

i.e. 10.5 = M-0.025(0.055)

Solve for M from the above equation

M =

Rounding off we get

10.50 kgs

Mean weight should be fixed as 10.50 kg.

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.