Here is one way Malena proved that 2(s+2) is equivalent to 4s+4

(1). 2(s+2)+2s=2s+4+2s

(2). =2s+2s+4

(3). =(2+2)s+4

(4). =4s+4

What properties of numbers and operations justify each step?

The properties of numbers and operations are justified for each step of Malena's is shown below

Step (1) 2(s+2)+2s ( for our convenient we are adding 2s here )

=2(s)+2(2)+2s ( by using the distributive property a(x+y)=ax+ay )

=2s+4+2s  

Step (2)  =2s+2s+4  ( by commutative property a+b=b+a )

Step (3) =(2+2)s+4  (by taking common term s )

Step (4) =4s+4  ( adding the like terms )

Step-by-step explanation:

Given that one way Malena proved that 2(s+2) is equivalent to 4s+4.

Malena's steps are

From the given expression 2(s+2)

Malena added 2s on the given expression.

Step (1) 2(s+2)+2s ( for our convenient we are adding 2s here )

=2(s)+2(2)+2s ( by using the distributive property a(x+y)=ax+ay )

=2s+4+2s  

Step (2)  =2s+2s+4  ( by commutative property a+b=b+a )

Step (3) =(2+2)s+4  (by taking common term s )

Step (4) =4s+4  ( adding the like terms )

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