The stopping distance of a car varies directly as the square of its speed. If a car traveling at 20mph requires 25.5ft to stop, find the stopping distance for a car traveling at 50mph.

159.375 feet.

Step-by-step explanation:

Let d represent stopping distance of a car and s represent speed of car.

We have been given that the stopping distance of a car varies directly as the square of its speed.

We know that two directly proportional quantities are in form , where y is directly proportional to x and k is constant of proportionality.

We can represent our given information in an equation as:

.

We are also told that a car traveling at 20 mph requires 25.5 ft to stop. We can represent this information in our equation as:

Now, we will substitute and in our equation and solve for d as:

Therefore, a car traveling at 50 mph requires 159.375 feet to stop.

6.5

step-by-step explanation:

you said it was in the question

~courtney

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.