Make a box-and-whisker plot of the data. 60,63,53,66,65,58,51,55,58,51,58,62 ,53,66,61,51,65,52,54,50

Step-by-step explanation:

To do this by hand, first sort data (you can use wolfram to do this).

Then divide data into four parts.

50, 51, 51, 51, 52, 53, 53, 54, 55, 58, 58, 58, 60, 61, 62, 63, 65, 65, 66, 66

Q1 = (52+53)/2 = 52.5

Q3 = (62+63)/2 =  62.5

IQR = 62.5 - 52.5 = 10

x >  Q3 + 1.5*IQR  or  x < Q1 - 1.5*IQR

=> There are no outliers.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

replication and blocking

step-by-step explanation: