What is the length of the hypotenuse of a right triangle with legs of lengths 7 and 8

The length of the hypotenuse is 10.6 units (approximately)

Step-by-step explanation: A right angled triangle can be solved by applying the Pythagoras theorem which states thus;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (the longest side) and AB and BC are the other two sides.

In this question, AB and BC are the other two sides, that is, 7 units and 8 units. Hence, to calculate the hypotenuse,

AC^2 = AB^2 + BC^2

AC^2 = 7^2 + 8^2

AC^2 = 49 + 64

AC^2 = 113

Add the square root sign to both sides of the equation

AC = 10.63

Therefore, the length of the hypotenuse is approximately 10.6 units

asdsad

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w