At the end of a recent WNBA regular season, the Phoenix Mercury had 12 more wins than losses. The number of wins they had was one more than two times the number of losses. How many regular season games did the Phoenix Mercury play during that season.

they played 34 regular season games.

Step-by-step explanation:

Let x represent the number of wins that the Phoenix Mercury had.

Let y represent the number of losses that the Phoenix Mercury had.

The Phoenix Mercury had 12 more wins than losses. It means that

x = y + 12

The number of wins they had was one more than two times the number of losses. It means that

x = 2y + 1- - - - - - - - - - -1

Substituting x = y + 12 into equation 1, it becomes

y + 12 = 2y + 1

2y - y = 12 - 1

y = 11

Substituting y = 11 into equation 1, it becomes

x = 2 × 11 + 1

x = 22 + 1

x = 23

Therefore, the total regular season games that the Phoenix Mercury played during that season is

23 + 11 = 34

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )