A clothing store had a rectangular clearance section with a length that is twice the width w. during a sale, the secrion is expanded to an area of 2w^2 + 19w+35ft^2. find the amount of the increase in the length and width of the clearance section

The length is increased by 5 feet and width is increased by 7 feet.

Step-by-step explanation:

Given:

Length of section is twice the width.

During sale the section is expanded to an area =

To find increase in length and width.

Solution:

Let the length of the section be =

width of the section =

Expression for area :

Factoring:

So, area of the section after increase can be given as

We know that length is twice the width, which means:

Substituting the value of in the factored expression of area.

Since area of triangle is product of length and width, so we have:

New length of section =

New width of the section =

Thus, length is increased by 5 feet and width is increased by 7 feet.

the answer is: the length is 5/6 yards.

give me a or a 5 star rating if this is correct!

step-by-step explanation:

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb