Ms. smith invested 25000 in two accounts one yielding 4% interest the other 12%.If she received a total of 2280 in interest at the end of the year how much did she invest in each account?

Ms Smith invested $9,000 in one account and $16,000 in the second account

Step-by-step explanation:

Now let us denote the amount she invested in the first account by "a" and denote the amount she invested in the second account by "b".

If she invested $25,000 in the 2 accounts, then:

a + b = $25000 call this equation (eqn)1

Again, the first account yielded extra 4% of what was invested.

Therefore 4/100 × a = 4a/100 (this is the amount the first account yielded)

The second account yielded extra 12% of the invested amount

Therefore 12%×b = 12b/100

If the total sum of the interest the 2 accounts yielded was 2280, then:

( 4a/100) + (12b/100) = 2280 let this be eqn 2

We now have simultaneous equations before us.

In eqn 1, making b the subject of the formula:

b = $25000 - a

Substitute b for $25000 - a in eqn 2

(4a/100) + [12(25000 - a)/100] = 2280

300000 - 8a = 228000

- 8a = 228000 - 300000

a = -72000/-8

a = $9000

Now, we substitute "a" for $9,000 in eqn 1

9000 + b = 25000

b = 25000 - 9000

b = $16,000

So, Ms Smith invested separate sums of $9,000 and $16000 in the two accounts

lol

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.