In still water a boat averages 18 miles per hour. it takes the same amount of time to travel 4 miles downstream, with the current, as it does 2 miles upstream, against the current, what is the rate of the water current

The rate of water current = 6 mi / h

Step-by-step explanation:

Speed of the boat in still water = u = 18 mi / h

Let Speed of the current = v

Now downstream speed is given by = u + v

And upstream speed is given by = u - v

Now time taken to travel 4 miles in downstream =    ----------------------(1)

And time taken to travel 2 miles in upstream =   ----------------------------(2)

Now from the question equation (1) = equation (2)

⇒ =

⇒ 4 u - 4 v = 2 u + 2 v

⇒ 2 u = 6 v

⇒ u = 3 v

⇒ given that u = 18 mi / h

⇒ v =

⇒ v = 6 mi / h

Thus the rate of water current = 6 mi / h

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!