A project’s critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17). What is the standard deviation on the critical path?

The standard deviation on the critical path = 0.834

Step-by-step explanation:

Variance of activity A () = 0.33

Variance of activity B () = 0.67

Variance of activity C () = 0.33

Variance of activity D () = 0.17

Thus the standard deviation on the critical path () = + +   +

                                                                               = + + +

                                                                              = 0.6956

                                                                              = 0.834

The standard deviation on the critical path = 0.834

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

here is your mark brainliest