-x + 4y = 10 and x - 3y = 11 using substitution

y = 21

x = 74

Step-by-step explanation:

-x + 4y = 10

x - 3y = 11

Let the first eqn be eqn 1 and the second be eqn 2

ie

- x + 4y = 10 eqn 1

x - 3y = 11 eqn 2

From eqn 1, make x the subject of the formula

Carrying x over the equal to in order to change the sign from - to +

4y - 10 = x

Substitute the value of x in eqn 2

4y - 10 - 3y = 11

Collecting like terms

4y - 3y = 11 + 10

y = 21

The value of y is 21

Then, substitute the value of y into eqn 1

-x + 4y = 10

-x + 4(21) = 10

-x + 84 = 10

84 -10 = x

In order to get rid of the - sign

x = 74

Therefore,

x = 74

y = 21

Step-by-step explanation:

hello : -x + 4y = 10 (*)

          x - 3y = 11...(**)

add(*) and(**) : y=21

put this value in(**) : x -3(21) = 11

x= 74

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: