find all ordered pair not only one!! TYSM

For the given set of equations, none of the ordered pairs are solutions for it.

Step-by-step explanation:

Step 1:

From the given question,

take this as equation 1,

, take this as equation 2.

Step 2:

We multiply equation 1 with 5 and equation 2 with 6, so we can cancel out the variable x in both equations. By doing this we get

, take this as equation 3.

,take this as equation 4.

When we add equations 3 and 4, the x variable is canceled out and y can be calculated.

Step 3:

Substituting this value of y in any of the previous equations we will get x's value.

Here this value of y is substituted in equation 1.

So we have and .

None of the given ordered pairs have the solution as (-4, -4), so it is no for all the ordered pairs given.

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%