What is the probability of obtaining threethree tailstails in a row when flipping a coin? Interpret this probability.
The probability of obtaining threethree tailstails in a row when flipping a coin is 0.1250.125.
(Round to five decimal places as needed.)
Interpret this probability.
Consider the event of a coin being flipped threethree times. If that event is repeated ten thousand different times, it is expected that the event would result in threethree tailstails about nothing time(s).

P=0.125

If it is repeated 10,000, it is expected "3 tails in a row" about 1,250 times.

Step-by-step explanation:

When flipping a coin a number of times, we can modeled this as a random variable with a binomial distribution.

In this case, we have to calculate the probability of 3 consecutive tails. If we define p as the probability of getting a tail (which has a value of p=0.5 if it is an unbiased coin), the probability of getting 3 tails in a row is:

If that event of "flipping a coin 3 times" is repeated 10,000 times, we can expect to have 3 tails in a row about 1,250 times:

because we expect 0.125 events of this type for every try, so we can multiply this probability (or expected frequency) by the number of trials and we get the expected number of events described.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

%40

step-by-step explanation: