13 POINTS!! I'M MAKING MYSELF BROKE FOR Y'ALL. Also, my last question today :)
How is the expression 6³³×6¹²÷6²⁰expressed as a power of 6?

6^25

Step-by-step explanation:

6³³×6¹²÷6²⁰

We know that a^b*a^c = a^(b+c)

6³³×6¹² = 6^45

We know that a^b ÷ a^c = a^(b-c)

6^45 ÷6²⁰ = 6^(45-20)

6^25

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

mx+89b(-98)nb

step-by-step explanation: