The difference of the square of a number and 4 is equal to 3 times that number. Find the negative solution.

The negative solution is x = –1.

Solution:

Let the number be x.

Square of a number = x²

3 times a number = 3x

Difference of square of a number and 4 = 3 times that number

Subtract 3x from both sides of the equation, we get

–3x can be written as x – 4x.

1st bracket have common term x and bracket have –4 common term.

Take common term x + 1 outside.

By zero factor principle, if AB = 0 then A = 0 or B = 0.

x + 1 = 0,   x – 4 = 0

x = –1,   x = 4

The negative solution is x = –1.

answer: it is 1: 47 pm

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)