F(x) = (two-fifths) Superscript x g(x) = (two-fifths) Superscript x – 3 Which statement about f(x) and its translation, g(x), is true? The range of g(x) is , {y | y > 0} and the range of f(x) is {y | y > –3}. The range of g(x) is , {y | y > 3} and the range of f(x) is {y | y > 0}. The asymptote of g(x) is the asymptote of f(x) shifted three units down. The asymptote of g(x) is the asymptote of f(x) shifted three units up.

C

Step-by-step explanation:

The asymptote of g(x) is the asymptote of f(x) shifted three units down.

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source