Water in a canal , 6m wide and 1.5m deep , flowing with a speed of 10km/h . How much area will it irrigate in 30 minutes , if 8 cm of standing water is needed.

The area covered by the canal in 30 mins is 562500 sq m

Step-by-step explanation:

Step 1 :

Given,

The canal's width = 6 meter

The canal's Depth is given as 1.5 meter

Speed of the water flowing = 10 kilometer per hour  

We need to determine the area which will be irrigated in 30 mins

Step 2 :

In one hour the canal flows 10 kilometer , therefore in 30 minutes it covers 5 kilometer = 5 × meter

Hence the volume of the water irrigated per 30 minutes = 6 × 1.5 × 5 ×

= 45 ×   cubic meter

The standing water is 8 centimeter = 8 ×  meter

Hence the area covered in 30 min = Volume ÷ the height of the standing water

= (45 × )  ÷ 8 ×   meter

= 562500 square meter

Step 3 :

The area covered by the canal in 30 mins is 562500 square meter

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.