A linear function has a slope of -g and a y-intercept of 3. How does this function compare to the linear function that is represented
by the equation Y+ 11 =-á (x-18)
O It has the same slope and the same y-intercept
O It has the same slope and a different y-intercept
O It has the same y-intercept and a different slope.
O It has a different slope and a different y-intercept
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place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

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