Show that f(x, y) = 5x eˣʸ is differentiable at (1, 0) and find its linearization there. Then use it to approximate f(1.1, −0.1).

The approximate f(1.1,-0.1) is 4.92.

Step-by-step explanation:

Since we have given that

at (1,0),

we get

Partial derivative would be

So,

Similarly,

So,

Now,

L(1.1,-0.1)=

and

f(1.1,-0.1) =

Hence, the approximate f(1.1,-0.1) is 4.92.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~