answer: integers are just whole numbers: positive, negative, and zero.
i = {-∞, -2, -1, 0, 1, 2, 3, ∞}
let x = 1st integer
let y = 2nd integer
x = 3y + 17 {equation 1}
xy = -24 {equation 2}
substitute 3y+17 in place of x n equation 2
and solve for y.
(3y+17)y = -24
3y2 + 17y = -24
3y2 + 17y + 24 = 0
from quadratic equation:
y = [-17±√(172-4(3)(24))]/(2(3))
y = (-17 ±√1)/6
y = (-17+1)/6 or y = (-17-1)/6
y = -16/6 or y = -18/6
y = -2 2/3 or y = -3
since we are dealing with
y = -3
x = 3y+17 = -9+17 = 8
the integers are -3, 8
step-by-step explanation: