The top of a ladder slides down a vertical wall at a rate of 0.675 m/s . At the moment when the bottom of the ladder is 3 m from the wall, it slides away from the wall at a rate of 0.9 m/s . How long is the ladder

L = 5 m

Step-by-step explanation:

The ladder, the vertical wall and the ground form a right triangle. We call A and B the ends points of the ladder ( at the wall, and the ground)

If we call L the lenght of the leadder, we get

L² = y² + x²

Taking derivatives on both sides of the equation

0 = 2y Dy/dt  +  2x Dx/dt

We know that Dy/dt = - 0,675 m/s (is sliding down , is decreasing)

And when x = 3 m  Dx/dt = 0,9 m/s

So we  can get y

0 = 2y*( -0,675) + 2*3*0,9

1,35y  =  5,4

y =   5.4 /1,35    ⇒   y = 4

And  L²  = y² + x²    ⇒  L  = √ (4)² + (3)²   ⇒  L √16 + 9

L = 5 m

tube or goog would be a great resource to with that question

d i think

step-by-step explanation: