The Friendly sausage Factory (FSF) can produce hot dogs at a rate of 5000 per day. FSF supplies hot dogs to local restaurants at a steady rate of 250 per day. The cost to prepare the equipment for producing hot dogs is $66. Annual holding costs are 45 cents per hot dogs. The factory operates 300 days a year. Find
a) The optimal run size
b) The number of runs per year
c) The length (in days) of a run

a). 4,812 hot dogs

b). 16 runs per year

c). 0.96

Step-by-step explanation: Optimal order quantity is found when annual setup cost equals annual holding cost.

Variables;

Q0= Optimal run size

D = Annual demand in units

S = Setup cost per order

H = Holding cost per unit per year

D is not given. So to get D=u×T; u= usage rate = 250 per day; T=300

Therefore D=250×300= 75000

S=$66

H=$0.45 per hot dog

T(year)=300 days

p= production rate5000 per day

a). Optimal run size = Q0 = √2DS/H √p/p-u = √2(75000)66/0.45 ×√5000/5000-250=4,690.41576 × 1.02597835=4,812.26502= 4,812(approximately)

b). Circle time= Q0/u= 4812/250= 19days

Number of runs/year= T(year)/Circe time= 300/19 15.7894737=16(approximately)

c). Runtime= Q0/p= 4812/5000= 0.96

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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