The area of a rectangle is 42 ft', and the length of the rectangle is 5 ft more than double the width. Find the dimensions of the rectangle.
Length: Ift

Length of the rectangle is 12 ft and width is 3.5 ft

Step-by-step explanation:

⇒ 42 = (5 + 2x)x

⇒ 42 = 5x + 2x²

⇒ 2x² + 5x - 42 = 0

⇒ 2x² + 12x - 7x - 42 = 0

⇒ 2x(x + 6) - 7(x + 6) = 0

⇒ (2x - 7)(x + 6) = 0

∴ x = -6, 7/2 (ignore the negative value)

⇒ Width is 3.5 ft

∴ Length is 5 + 2 × 3.5 = 12 ft

answer: 59

step-by-step explanation:

f(x) = y

f(-3) = -5

step-by-step explanation: