I need help with this (Image Attached)

55,98,27

Step-by-step explanation:

To solve for the angles we must first find y with this equation

3y+5+2y-7=153

We can simplify this

5y-2=153

153+2=155

155/5=31

y=31

We now know y and can plug it into the angles

<A=2y-7

2(31)-7

62-7

55

<A=55

<B=3y+5

3(31)+5

93+5

98

<B=98

Now time for the last angle

Since angle BCA and DCB are next to each other they add up to 180

153+x=180

180-153=27

x=27

<BCA=27

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

it shoild be o

step-by-step explanation: