{40x+3y=10
{ 20x−7y=5

System of equatio
Please explain

x = , y = 0

Step-by-step explanation:

Given the 2 equations

40x + 3y = 10 → (1)

20x - 7y = 5 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the x- term

- 40x + 14y = - 10 → (3)

Add (1) and (3) term by term, that is

17y = 0 ⇒ y = 0

Substitute y = 0 into either of the 2 equations and solve for x

Substituting y = 0 in (1)

40x + 3(0) = 10, that is

40x = 10 ( divide both sides by 40 )

x = =

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.