Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x)^2 = x^2

121 + 121^2 - 121(2)x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)