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A)Corresponding Angles Theorem; ∠AGF and ∠EHD are congruent
B)Alternate Exterior Angles Theorem; ∠EGB and ∠EHD are congruent
C)Corresponding Angles Theorem; ∠EGB and ∠EHD are congruent
D)Alternate Exterior Angles Theorem; ∠AGF and ∠EHD are congruent

Corresponding Angles Theorem; ∠AGF and ∠EHD are congruent

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Explanation:

∠EGB and ∠EHD are angles that are both on the right hand side of the transversal line EF. Also, these two angles are above their adjacent parallel line. In other words, ∠EGB is above line AB, while ∠EHD is above line CD.

So this all means ∠EGB and ∠EHD are corresponding angles. By the corresponding angles theorem, we can go from AB and CD being parallel to ∠EGB = ∠EHD.

Earlier it was shown that ∠AGF = ∠EGB. Combine this with ∠EGB = ∠EHD, and we can effectively chain the statements together to end up with ∠AGF = ∠EHD.

In terms of a math term, we used the transitive property of equality. This property says that if a = b and b = c, then a = c. You can think of three towns A, B, C. If you go from town A to town B, then town B to town C, then overall you went from town A to town C. We can write it as such which simplifies to

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!