The equation of line p is y = x − 1 .
Line q is parallel to line p and passes through (–2, 8) .
What is the equation of line q ?
Write the equation in slope-intercept form. Write the numbers in the equation as proper fractions, improper fractions, or integers.

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line p is

y = x - 1

Comparing with the slope intercept form, slope = 1

If two lines are parallel, it means that they have the same slope. Therefore, the slope of line q passing through (- 2, 8) is 1

To determine the y intercept, we would substitute m = 1, x = - 2 and

y = 8 into y = mx + c. It becomes

8 = 1 × - 2 + c

8 = - 2 + c

c = 8 + 2 = 10

The equation becomes

y = x + 10

y = x + 10

Step-by-step explanation:

Slope = 1

y = x + c

When x = -2, y = 8

8 = -2 + c

c = 10

y = x + 10

dd

step-by-step explanation:

dd

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.