Please help!!

a ball is thrown with a slingshot at a velocity of 95 ft/sec at an angle 25 degrees above the ground from a height of 6 ft. approximately how long does it take for the ball to hit the ground? acceleration due to gravity is 32 ft/s^2.

2.82 seconds (3 sf)

Step-by-step explanation:

s = ut + 0.5at²

6 = -95(sin25)t + 0.5(32)t²

16t² - 40.14873487t - 6 = 0

t = 2.818501699, -0.1419193751

t is time so can't be negative.

Therefore, t = 2.82s (3 sf)

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: