Please help, I will give more points!

  length and width are (x +4) and (2x -3)

Step-by-step explanation:

Factoring a trinomial with a leading coefficient that is not 1 can be a little tricky. Basically, you want to find factors of the product of the first and last coefficients that have a sum equal to the middle one.

Here, that product is (2)(-12) = -24. Factors of -24 are ...

  -24 = -1·24 = -2·12 = -3·8 = -4·6

The sums of these factor pairs are, respectively, 23, 10, 5, 2. We are interested in the pair whose sum is 5: -3 and 8. Now, we can rewrite the middle term using that sum:

  2x^2 -3x +8x -12

and factor pairs of terms:

  = x(2x -3) +4(2x -3) = (x +4)(2x -3)

This is the factorization the problem is looking for.

The length and width of the pool are (x +4) and (2x -3).

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