Tamara invests $8000 in two different accounts. The first account has a simple interest rate of 3% and
the second account has a simple interest rate of 2%. How much did she invest in each account if the
interest earned in them is the same at the end of one year?

she invested $3200 at 3% and $4800 at 2%

Step-by-step explanation:

Let x represent the amount that she invested in the account earning 3% interest.

Let y represent the amount that she invested in the account earning 2% interest.

Tamara invests $8000 in two different accounts. The first account has a simple interest rate of 3% and

the second account has a simple interest rate of 2%. This means that

x + y = 8000

y = 8000 - x

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 3% interest,

P = $x

T = 1 year

R = 3℅

I = (x × 3 × 1)/100 = 0.03x

Considering the account paying 2% interest,

P = $y

T = 1 year

R = 2℅

I = (y × 2 × 1)/100 = 0.02y

If she earns the same interest from both accounts, it means that

0.03x = 0.02y

x = 0.02y /0.03 - - - - - - - - - - - - -1

Substituting y = 8000 - x into equation 1, it becomes

x = 0.02(8000 - x)/0.03

0.03x = 0.02(8000 - x)

0.03x = 160 - 0.02x

0.03x + 0.02x = 160

0.05x = 160

x = 160/0.05

x = 3200

y = 8000 - x = 8000 - 3200

y = 4800

plz yuo

step-by-step explanation:

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: