The length of a room is two times its breadth and breath is 2 times its height. if the volume of the room is 512 m*3.how much is the cost of plastering the wall at 5.50 per m*2?

It will cost 2,464 currency for plastering 448 of the wall.

Step-by-step explanation:

Step 1:

The volume of this room is determined by multiplying its length, breadth, and height.

From the question;

So

Step 2:

The volume of the room ,

Substituting the values of length and breadth in the above equation, we get

So

So l = 16 m, w = 8 m and h = 4 m.

Step 3:

If each of the wall costs 5.50, we need to calculate the surface area of the room.

There are six sides of the room (2 sets of 3 sides)

Area of the set =

Area of the set =

Area of the set =

The Surface area of these three sets = 128 + 64 + 32 = 224 .

Since there are two sets,

The total surface area = .

Step 4:

If each of the wall costs 5.50,

448 costs; currency.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.