The length of a rectangular garden is 10 feet longer than its width. If the gardens perimeter is 212 feet, what is the area of the garden in square feet?

Area = A = 2784

Step-by-step explanation:

Let,

length of a rectangular garden = l

width of a rectangular garden = w

Given Data:

Perimeter = 212 feet

According to given condition

l = w+10

To find out:

Area = A = ?

Formula:

P=2(l+w)

Area = A = l×w

Solution:

P=2(l+w)

212 = 2(w+10+w)

212 = 2(10+2w)

212 = 20+4w

212 - 20 = 4w

w = 192/4

w = 48 feet

l = w+10

l = 48 + 10

l = 58 feet

Area = A = l×w

Area = A = 58×48

Area = A = 2784

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47