Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 120 passengers. The probability that a passenger does not show up is 0.10, and the passengers behave independently. Round your answers to four decimal places (e. g. 98.7654).

Answer is 0.9738

Step-by-step explanation:

Given, n == 125

Probability that passenger will not show up, q = 0.10

Probability that passenger will show up, p = 1 - q

                                                                      = 1 - 0.10

                                                                      = 0.9

The probability that the flight departs with empty seats.

μ = np  ==>  125 x 0.9  ==>  112.5

σ = √npq ==> √125x0.9x0.1  ==> 3.354

∴ P( Z ≤ )

P ( Z ≤ 1.94 )

= 0.9738

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2